x2+6x=14 by completing square method
Answers
Answered by
3
Answer:
x = -3 + sqrt(23) or -3 - sqrt(23)
Step-by-step explanation:
Given x^2 + 6x = 14
x^2 + 2 × x × 3 = 14
x^2 + 2 × x × 3 + 3^2 = 14 + 3^2
(x+3)^2 = 23
So x+3 = sqrt(23) or - sqrt(23).
Hence the answer.
Answered by
0
x^2 + 6x = 14
=> x^2 + 6x + (6 × 1/2)^2 = 14 + (6 × 1/2)^2
=> x^2 + 6x + 3^2 = 14 + 3^2
=> (x + 3)^2 = 14 + 9
=> (x + 3)^2 = 23
=> x + 3 = ± √23
=> x = ± √23 - 3
➖➖➖➖➖➖➖➖➖
x = √23 - 3
and
x = -√23 - 3
=> x^2 + 6x + (6 × 1/2)^2 = 14 + (6 × 1/2)^2
=> x^2 + 6x + 3^2 = 14 + 3^2
=> (x + 3)^2 = 14 + 9
=> (x + 3)^2 = 23
=> x + 3 = ± √23
=> x = ± √23 - 3
➖➖➖➖➖➖➖➖➖
x = √23 - 3
and
x = -√23 - 3
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