x²+6x-16
factorise please help fast
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✪ Question ✪
Factorise: x²+6x-16
✪ To find ✪
The factors.
✪ Solution ✪
x²+6x-16
Consider the form x²+bx+c. Find a pair of integers whose product is c and sum is b. In this case, we have to find a pair of integers whose product is (-16) and sum is 6.
The integers are 8 and (-2).
Because,
8×(-2) = (-16), and
8+(-2) = (8-2) = 6.
So,
x²+6x-16
= x²+8x-2x-16
In x²+8x-2x-16, we can take x common from x²+8x and (-2) from (-2x-16).
So,
x²+8x-2x-16
= x(x+8)-2(x+8)
In x(x+8)-2(x+8), we can take (x+8) as common.
So,
x(x+8)-2(x+8)
= (x+8)(x-2)
✪ Hence ✪
x²+6x-16 = (x+8)(x-2)
✪ Therefore ✪
x²+6x-16 when factorised gives (x+8)(x-2).
๑ Hope this helps you. ๑
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