Question

X2-6x-27 factorize the following using factorization method

Answer 1

Answer:

x= -3, 9

Step-by-step explanation:

$x^{2} -6x-27=0\\x^2-9x+3x-27=0\\x(x-9)+3(x-9)=0\\(x+3)(x-9)=0\\x+3=0\\x=-3\\x-9=0\\x=9$

Answer 2

Answer:

The roots of the equation are x = -3 or x = 9

Step-by-step explanation:

The equation is :

${x}^{2} - 6x - 27 = 0$

${x}^{2} - 9x + 3x - 27 = 0$

$x(x - 9) + 3(x - 9) = 0$

$(x + 3) \times (x - 9) = 0$

$x = - 3 \: or \: x = 9$