Question

x2-6x-3=0, solve using quadratic equation formula method​

Answer 1

Answer:

hope this helps dear

mark as brainliest

Answer 2

x²-6x-3=0

compare equation with ax²+bx+c=0

a=1,b=-6,c=-3

b²-4ac=(-6)²-4×1×(-3)

= 36+12

=48

by using Formula,

x=-b+or-√b²-4ac

2a

x=-(-6)+or-√48

2×1

x=6+or-√48

2

x=6+or-√16×3

2

x=6+or-4√3

2

x=2(3+or-2√3)

2

x=(3+or-2√3)

x=3+2√3 or x=3-2√3

x=3+2√3 or x=3-2√3 are roots of quadratic equation.