Question

X2-6x+4=0 is a quadratic equation

Answer 1

Answer:

Answer to your question:

{x}^{2} - 6x + 4 = 0

Add and subtract (6/2)^2,

{x}^{2} - 6x + {3}^{2} - {3}^{2} + 4 = 0

{(x - 3)}^{2} - 9 + 4 = 0

{(x - 3)}^{2} - 5 = 0

{(x - 3)}^{2} - { \sqrt{5} }^{2} = 0

(x - 3 + \sqrt{5} )(x - 3 - \sqrt{5}) = 0

x = 3 - \sqrt{5}

x = 3 + \sqrt{5}

Hope it helps ^_^

Ur answer is here.....!!!!!

Plz Mark as brainliest....!!!!