Question

x2-6x+4=0 solve the equation by completing square method

Answer 1

Heya!!!

Answer to your question:
${x}^{2} - 6x + 4 = 0$
Add and subtract (6/2)^2,
${x}^{2} - 6x + {3}^{2} - {3}^{2} + 4 = 0$
${(x - 3)}^{2} - 9 + 4 = 0$
${(x - 3)}^{2} - 5 = 0$
${(x - 3)}^{2} - { \sqrt{5} }^{2} = 0$
$(x - 3 + \sqrt{5} )(x - 3 - \sqrt{5}) = 0$
$x = 3 - \sqrt{5}$
$x = 3 + \sqrt{5}$
Hope it helps ^_^

Answer 2

X^2-6x=-4
X^2-6x+3^2=-4+3^2
(X-3)^2=5
X=3+root5
X=3-root5

Mark brainliest pls