Question

x²-6x-40


pls tell me full solution pls pls pls ​

Answer 1

Answer:

${x}^{2} - (10 - 4)x - 40 \\ \\ = {x}^{2} - 10x + 4x - 40 \\ \\ = x(x - 10) + 4(x - 10) \\ \\ = (x - 10)(x + 4) \\ \\ either \: x - 10 = 0 \\ \\ = > x = 10 \\ \\ or \: x + 4 = 0 \\ \\ = > x = - 4$

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Answer 2

Answer:

x²-6x-40

x² -10x + 4x - 40 =0

x(x -10) + 4(x-10) =0

(x-10) (x+4) =0

x= 10 , -4

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