Question

x2+6x-5040=0 solve this quadratic equation

Answer 1

$<marquee>heya!!!</marquee>$

Answer to your question:
${x}^{2} + 6x - 5040 = 0$
$d = {b}^{2} - 4ac$
$d = {6}^{2} - 4(1)(5040)$
$d = 36 - 20160$
$d = - 20124$
which is less than 0.

Hence, this equation has no real roots.

Hope it helps ^_^

Answer 2

here is ur answer
mate