Math, asked by shruti10dhiman, 7 months ago

x2+6x+7=0 completing square method

Answers

Answered by SHAANbrainly
2

Hey friend!

Here is your answer:

To solve x² + 6x + 7 = 0 by completing square method

Information:

Steps : For ax² + bx + c = 0

  • Step 1: Divide all terms by a .
  • Step 2: Move the number term (c/a) to the right side of the equation.
  • Step 3: Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation

Now,

x^2 + 6x + 7 = 0

\implies x^{2} + 2 \ * \ 3x + 7 = 0

\implies x^{2} + 2 \ * \ 3 + 7 + 2 - 2 = 0

\implies x^{2}  + 2 \ * \ 3 + 9 - 2 = 0

\implies (x + 3 )^{2} -2 = 0\\\\\implies (x + 3)^2 - (\sqrt{2})^2 = 0\\\\\implies (x + 3 - \sqrt{2})(x + 3 + \sqrt{2}) = 0\\\\\implies Either\ ( x +  3 - \sqrt{2} = 0 \ or \  (x + 3 + \sqrt{2}) = 0\\\\\implies Either\ x =  \sqrt{2} - 3 \ or \ x = - 3 -  \sqrt{2}

Answer : x = √2 - 3, -3 - √2

I hope it helps you

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