Question

x2 - 6x +8 = 0 solve by factorization method​

Answer 1

Answer:

Solution :-

➜ x² - 6x + 8 = 0

➞ x² - (4 + 2)x + 8 = 0

➞ x² - 4x - 2x + 8 = 0

➞ x(x - 4) - 2(x - 4) = 0

➞ (x - 4) (x - 2) = 0

➞ (x - 4) = 0

➞ x - 4 = 0

➞ x = 4

Either,

➞ (x - 2) = 0

➞ x - 2 = 0

➞ x = 2

∴ The answer of this question is x = 4, 2

Answer 2

${ \boxed{ \huge{ { \rm{ \underbrace{ Given}}}}}}$

$\large \underline {\mathcal {{{\color{orange}{\bf \Large \hookrightarrow \: \: {x}^{2} \: - \: 6x \: + \: 8 \: = \: 0}}}}}$

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Now , using the splitting the middle term method.

$\bf \Large \implies \: \: {x}^{2} \: - \: 6x \: + \: 8 \: = \: 0$

$\bf \large \implies \: \: {x}^{2} \: - \: 4x \: - 2x \: + \: 8 \: = 0$

$\bf \large \implies \: \:x \: (x - 4) \: - 2 \: (x - 4)$

$\bf \large \implies \: \:(x - 2) \: \: (x - 4) \: = \: 0$

$\bf \large \implies \: \:x - 2 = 0 \: \: and \: \: x - 4 = 0$

$\bf \large \implies \: \:x \: = \: 2 \: \: \: and \: \: \: x \: = 4$