Question

x2+6x+8
resolve the factors​

Answer 1

Given :-

${x}^{2} + 6x + 8 = 0$

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

${x}^{2} + 4x + 2x + 8 = 0 \\ \\ x(x + 4) + 2(x + 4) = 0 \\ \\ (x + 4)(x + 2) = 0$

Now split it into possible cases

$(x + 4) = 0 \\ \\ \\ (x + 2) = 0$

Hence,

$x_1 = ( - 4) \\ \\ \\ x_2 = ( - 2)$

Extra information :-

• A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

Answer 2

Answer:(x+2)(x+4)

Step-by-step explanation: x2+6x+8

factors of 8 are 4 and 2 which fit the equation.

(x2+4x)+(2x+8)

x(x+4) +2(x+4)

thus, the factors are

(x+2)(x+4)