Question

x2+6x+8÷x2+3x+2=3/5(x is not equlq to 2,-1​)​

Answer 1

Answer:

Given, 3x2+1x2−6x+83x2+1x2−6x+8

On dividing, we get

3x2+1x2−6x+8=3+18x−23x2−6x+8.....(i)3x2+1x2−6x+8=3+18x−23x2−6x+8.....(i)

Now, 18x−23(x−2)(x−4)=Ax−2+Bx−418x−23(x−2)(x−4)=Ax−2+Bx−4

⇒18x−23=A(x−4)+B(x−2)⇒18x−23=A(x−4)+B(x−2)

⇒18x−23=(A+B)x−4A−2B⇒18x−23=(A+B)x−4A−2B

Equating the coefficient of x and constant term, we get

A + B = 18

- 4 A - 2 B = -23

On solving these equations, we get

A=−132,B=492A=−132,B=492

∴18x−23(x−2)(x−4)=−132(x−2)+492(x−4)∴18x−23(x−2)(x−4)=−132(x−2)+492(x−4)

Then, from Eq. (i), we get

3x2+1x2−6x+8=3−132(x−2)+492(x−4)

Answer 2

Answer:

x = -17/2

Step-by-step explanation:

• i think that the question is x2+6x+8÷x2+3x+2=3/5(x is not equal to -2,-1)

• given equations: x² + 6x + 8 and x² + 3x + 2

• x² + 6x + 5 = (x + 2)(x + 4) (by factorisation) ..........(1)

• x² + 3x + 2 = (x + 1)(x + 2) (by factorisation) ..........(2)

• (1)/(2) = (x + 2)(x + 4)/(x + 1)(x + 2)

• = (x + 4)/(x + 1). (because given that x is not equal to 2, -1)

• according to question (x + 4)/(x + 1) = 3/5

• by cross multiplication we get,

• 5x + 20 = 3x + 3

• 2x = -17

• x = -17/2

hope this answer is helpful to you