Question

x²-6x+9=0 completing square solution​

Answer 1

Step-by-step explanation:

$\huge\underline{\underline{\sf ANSWER}} \\ {x}^{2} - 6x + 9 = 0 \\ {( \frac{1}{2} \times coeff \: of \: x)}^{2} \\ {( \frac{1}{2} ( - 6))}^{2} \\ {( - 3)}^{2} \\ 9 \\ \\ {x}^{2} - 6x + 9 - 9 + 9 = 0 \\ {(x - 3)}^{2} = 0 \\ x - 3 = 0 \\ x = 3$

Answer 2

Answer:

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Step-by-step explanation:

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