Question

x²-6x+9≥0. find the range. ​

Answer 1

Answer:

range is -2

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Answer 2

R

Step-by-step explanation:

Question :-

find Range of x² - 6x + 9 ≥ 0

using factorization method ;

x² - 3x - 3x + 9 ≥ 0

x(x - 3) -3(x - 3) ≥ 0

(x - 3)(x - 3) ≥ 0

(x - 3)² ≥ 0

As we know that square of a real number will always be greater than or equal to 0, so;

Range of x² - 6x + 9 will be R.

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