Question

x2+6x+9 by completing the square​

Answer 1

$= > {x}^{2} + 6x = - 9$

$= > {x}^{2} + 2( \frac{6}{2})x + {3}^{2} = - 9 + {3}^{2}$

$= > {(x + 3)}^{2} = - 9 + 9$

$= > {(x + 3)}^{2} = 0$

$x + 3 = 0$

$= - 3$

Hope this answer is helpful.