Question

x2 - 6x2 + 11x - 6 = 0). Factorize it simply
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Answer 1

Answer:

x cube will be there otherwise it will not be solved.

Good morning

Answer 2

${ \large{ \mathtt{ {x}^{3} - {6x}^{2} + 11x - 6 = 0}}}$

Here,

${ \large{ \mathbf{(x - 1) \: \: is \: \: its \: \: factor.}}}$

Thus,

$= > { \boxed{ \large{ \mathtt{ {x}^{3} - {x}^{2} - {5x}^{2} + 5x + 6x - 6}}}} \\ \\ = > { \boxed{ \large{ \mathtt{ {x}^{2}(x - 1) - 5x(x - 1) + 6(x - 1) }}}} \\ \\ = > { \boxed{ \large{ \mathtt{(x - 1)( {x}^{2} - 5x + 6 )}}}} \\ \\ = >{ \boxed{ \large{ \mathtt{(x - 1)( {x}^{2} - 2x - 3x + 6)}}}} \\ \\ = > { \boxed{ \large{ \mathtt{ (x - 1)[x(x - 2) - 3(x - 2)]}}}} \\ \\ = >{ \boxed{ \large{ \red {\mathtt{(x - 1)(x - 2)(x - 3)}}}}}$