Question

-x²+6x²+ 8-12x
Values of x?
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Answer 1

Answer:

this quadratic equation has no real roots

as discriminant,D<0

Step-by-step explanation:

-x^2+6x^2+8-12x

=5x^2-12x+8

D=b^2-4ac=(-12)^2-4(5)(8)=144-160=-16<0