Question

X2+6x2 +ky+6 is exactly divisible by ( x+2), then k=

Answer 1

I guess the polynomial is

x³+6x²+kx+6 ÷(x+2)

when f(x) is exactly divisible by x+a then

f(-a) =0

(-2)³+24 -2k+6 =0

-8+24-2k+6=0

2k = 22

k=11