Question

x²-7√2x-16=0
what is the value of x?
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Answer 1

values of x will be (√2)⁷ , -√2

Answer 2

Answer:

$x^2-7\sqrt{2}x-16=0$

       $\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are:}$

             $x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

        $\mathrm{Where},\: \: a=1,\:b=-7\sqrt{2},\:c=-16$

$x=\dfrac{-\left(-7\sqrt{2}\right)\pm \:9\sqrt{2}}{2\times1}$

$x=\dfrac{-\left(-7\sqrt{2}\right)+9\sqrt{2}}{2\times1}=\dfrac{16\sqrt{2}}{2}=8\sqrt{2}$

$x=\dfrac{-\left(-7\sqrt{2}\right)-9\sqrt{2}}{2\times1}=\dfrac{-2\sqrt{2}}{2}=-\sqrt{2}$

$x=8\sqrt{2},\: -\sqrt{2}$

$\mathrm{@rohangupta0424}$