Math, asked by ajeeth4129, 1 year ago

X²+7x-1=0 find the value of discriminant

Answers

Answered by Anonymous
6
here is your answer by Sujeet yaduvanshi,
Here
a=1
b=7
c=-1

Then,
A/Q
Discriminant =b²-4ac

= (7)²-4.1.-1
= 49-4(-1)
= 49+4
= 53


that's all
Answered by SANDHIVA1974
1

Question :-

✎ Which of the following is the value of the discriminant for x² + 7x + 1 = 0 :-

A) -5

B) 17

C) 45

Given :-

x² + 7x + 1 = 0

Find Out :-

What is the discriminate value of that equation.

Solution :-

✭ x² + 7x + 1 = 0

here,

⊙ a = 1

⊙ b = 7

⊙ c = 1

As we know that :

\red{ \boxed{\sf{Discriminate\: (D) =\: b^2 - 4ac}}}

By putting values we get,

➙ Discriminate = (7)² - 4(1)(1)

➙ Discriminate = 49 - 4 × 1 × 1

➙ Discriminate = 49 - 4

{\small{\bold{\purple{\underline{Discriminate = 45}}}}}

Henceforth, the discriminate value of that equation is 45.

Correct options is C) 45.

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