X²+7x-1=0 find the value of discriminant
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Answer:
The value of the discriminant of the Quadratic equation = 53
Step-by-step explanation:
Quadratic Equation:
The polynomial equation of degree 2 in one variable is called a Quadratic equation.
- The general form of Quadratic equation is ax²+bx+c = 0
Discriminant:
- The Discriminant of the Quadratic equation is D = b²- 4ac
Discriminant and Nature of roots:
- If the discriminant is positive, D>0 then the Quadratic equation has Distinct and real roots.
- If the discriminant is negative, D<0 then the Quadratic equation has Distinct and complex roots.
- If the discriminant is equal to zero, D=0 then the Quadratic equation has two equal roots.
Given equation is x²+7x-1 = 0
Compare the given equation with general Quadratic equation.
a = 1, b = 7, c = -1
Discriminant value of the equation x²+7x-1 = 0 is
b²- 4ac = (7)²- 4(1)(-1)
= 49 + 4
= 53 > 0
The value of the discriminant of the Quadratic equation = 53
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