Question

x²+7x+10=0, using middle term factorisation​

Answer 1

Explanation:

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Answer 2

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Factoring x2-7x+10

The first term is, x2 its coefficient is 1 .

The middle term is, -7x its coefficient is -7 .

The last term, "the constant", is +10

Step-1 : Multiply the coefficient of the first term by the constant 1 • 10 = 10

Step-2 : Find two factors of 10 whose sum equals the coefficient of the middle term, which is -7 .

-10 + -1 = -11

-5 + -2 = -7 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and -2

x2 - 5x - 2x - 10

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-5)

Add up the last 2 terms, pulling out common factors :

2 • (x-5)

Step-5 : Add up the four terms of step 4 :

(x-2) • (x-5)

Which is the desired factorization

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