Question

X²+7x+10 verify the relationship ​

Answer 1

✪AnSwEr

${\tt{\red{\underline{\large{Given}}}}}$

A polynomial

X²+7x+10

${\sf{\green{\underline{\large{To\:Verify}}}}}$

Relationship between cofficient

${\sf{\pink{\underline{\Large{Explanation}}}}}$

Let the zeroes of the polynomial be

$\tt\alpha{and}\betaαandβ</p><p>$

Then,

$\tt\alpha{+}\beta\frac{-b}{a}$

$\tt\alpha{\times}\beta{=}\frac{c}{a}$

Here,

a=1

b=7

C=10

☞

$\tt\alpha{+}\beta=\dfrac{{-b}}{a}\dfrac{-1}{7}$

$\tt\alpha{+}\beta{=}\dfrac{-(Cofficient\:of\:X)}{Cofficient\:of\:x^2}$

$\tt\alpha{\times}\beta{=}\dfrac{10}{1}</p><p>$

$\tt{\large\alpha{\times}\beta{=}\dfrac{Constant\:term}{Cofficient\:of\:x^2}}$

Hence,relation verified

Answer 2

${\tt{\pink{\underline{\large{Given}}}}}$

A polynomial X²+7x+10

${\sf{\blue{\underline{\large{To\:Verify}}}}}$

• Relationship between the cofficient

${\sf{\orange{\underline{\Large{Explanation}}}}}$

• Let the zeroes of the polynomial be$\tt\alpha{and}\beta$

Then,

$\tt\alpha{+}\beta\frac{-b}{a}$

&

$\tt\alpha{\times}\beta{=}\frac{c}{a}$

Here,

a=1

b=7

C=10

$\tt\alpha{+}\beta=\dfrac{{-b}}{a}\dfrac{-1}{7}$

$\tt\alpha{+}\beta{=}\dfrac{-(Cofficient\:of\:X)}{Cofficient\:of\:x^2}$

&

$\tt\alpha{\times}\beta{=}\dfrac{10}{1}$

$\tt{\large\alpha{\times}\beta{=}\dfrac{Constant\:term}{Cofficient\:of\:x^2}}$

→Hence,verified✓✓