Question

X2+7x+12=0 please find the answer guys​

Answer 1

Answer:

${x}^{2} + 7x + 12 = 0 \\ \\ = > {x}^{2} + (4 + 3)x + 12 = 0 \\ \\ = > {x}^{2} + 4x + 3x + 12 = 0 \\ \\ = > x(x + 4) + 3(x + 4) = 0 \\ \\ = > (x + 4)(x + 3) = 0 \\ \\ either \: x + 4 = 0 \\ \\ = > x = - 4 \\ \\ or \: x + 3 = 0\\ \\ = > x = - 3$

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Answer 2

Answer:

Here's your answer in the attachment

I hope that this will help u