Question

x2-7x+12=0 quadratic equations method​

Answer 1

Step-by-step explanation:

according to question :-

x^2 - 7x + 12 = 0

x^2 - 4x - 3x + 12 = 0

x(x-4) -3(x-4) = 0

(x-4) (x-3) = 0

now if :-

x-4 = 0

then x = 4

and if :-

x-3 = 0

then x = 3

so value of x = 4,3

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Answer 2

Step-by-step explanation:

x² - 7x + 12 = 0

=> x² - (4 + 3)x + 12 = 0

=> x² - 4x - 3x + 12 =0

=> x(x - 4) - 3(x - 4) = 0

=>(x - 4)(x - 3) = 0

Either. or

x - 4 = 0 (x - 3) = 0

=>x = 4 => x = 3

So, required value of x is 4 or 3

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