x2-7x+12 please solve this question
Answers
Answered by
4
hey
x²-(4+3)x+12=0
x²-4x-3x+12=0
x(x-4)-3(x-4)=0
(x-4)(x-3)=0
if x-4=0
x=4
or if x-3=0
x=3
hope dis help
x²-(4+3)x+12=0
x²-4x-3x+12=0
x(x-4)-3(x-4)=0
(x-4)(x-3)=0
if x-4=0
x=4
or if x-3=0
x=3
hope dis help
Answered by
1
X^2-7x+12
X^2-4x-3x+12
X(x-4)-3(x-4)
X-4=0, x-3=0
X=4, x=3
Hope it HELPS you.
X^2-4x-3x+12
X(x-4)-3(x-4)
X-4=0, x-3=0
X=4, x=3
Hope it HELPS you.
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