Question

x2-7x-18 by x-9 divide polynomials by binomial
using factor method

Answer 1

GIVEN :

$\frac{x^2-7x-18}{x-9}$ divide polynomials by binomial  using factor method

TO FIND :

The factors when $\frac{x^2-7x-18}{x-9}$ divide polynomials by binomial  using factor method

SOLUTION :

Given polynomial is $\frac{x^2-7x-18}{x-9}$

By Factorisation we can solve it :

$\frac{x^2-7x-18}{x-9}$

$=\frac{x^2-9x+2x-18}{x-9}$

$=\frac{x(x-9)+2(x-9)}{x-9}$

$=\frac{(x-9)(x+2)}{x-9}$

= x+2

⇒ $\frac{x^2-7x-18}{x-9}=x+2$

We can write it as $x^2-7x-18=(x-9)(x+2)$

Let $p(x)=x^2-7x-18=(x-9)(x+2)$

Since x+2 is a factor of the given polynomial,

Now put x=-2 in $x^2-7x-18$

$=(-2)^2-7(-2)-18$

=4+14-18

=18-18

=0

∴ x+2 is also a factor of p(x)

Answer 2

question x^2-7x-17 by x-9