X²-7x+3=0 solve quadratic equation
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Step-by-step explanation:
SOLUTION:-
x^2-7x+3=0
we know roots of the equation: -b+√(b^2-4ac)/2a and-b-√(b^2-4ac)/2a
so the roots are;
1st root is : -(-7)+√(-7^2-4.1.3)/2.1
=7+√(49-12)/2
=7+√37/2
2nd root is: -(-7)-√(-7^2-4.1.3)/2.1
=7-√37/2
mark as brainlist plz mate
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