Question

x²-7x-8 factories the problem​

Answer 1

Given :

${x}^{2} - 7x - 8 = 0$

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

${x}^{2} - 7x - 8 = 0 \\ {x}^{2} - 8x + x - 8 = 0 \\ x(x - 8) + 1(x - 8) = 0 \\ (x - 8)(x + 1) = 0$

Hence,

$x_1 = 8 \\ x_2 = - 1$

Extra information :-

• A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

Answer 2

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Question}}}}}}}}$

x²-7x-8 factories the problem

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Solution}}}}}}}}$

$\sf\implies x^2 - 7x - 8$

$\sf\implies x^2 - 8x + x - 8$

$\sf\implies x(x-8)+1(x-8)$

$\sf\implies(x + 1 )(x - 8)$

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