Question

x²-8x+12
can somebody factories this for me ​

Answer 1

${x}^{2} - 8x + 12 = 0 \\ \\ {x}^{2} - 6x - 2x + 12 = 0 \\ \\ x(x - 6) - 2(x - 6) = 0 \\ \\ (x - 2)(x - 6) = 0$

#lovelove!

Answer 2

$\huge\mathbb{Answer}$

${x}^{2} - 8x + 12 = 0$

${x}^{2} - 6x - 2x + 12 = 0$

$x(x - 6) - 2(x - 6) = 0$

$(x - 2)(x - 6) = 0$

$x - 2 = 0 \: and \: x - 6 = 0$

$x = 2 \: and \: x = 6$

$\huge{Divya}$❤