Question

x2 +8x +16 factories ​

Answer 1

$\longmapsto\tt{x²+8x+16}$

$\longmapsto\tt{x²+4x+4x+16}$

$\longmapsto\tt{x(x+4)+4(x+4)}$

$\longmapsto\tt{x+4=0}$

$\longmapsto\tt{x=-4}$

Answer 2

Solution :-

$\longrightarrow {x}^{2} + 8x + 16 \\ \\ \longrightarrow {x}^{2} + 4x + 4x + 16 \\ \\ \longrightarrow x(x + 4) + 4(x + 4) \\ \\\longrightarrow (x + 4)(x + 4)$

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Roots of this Polynomial :-

$\bold \longrightarrow x + 4 = 0 \\ \\ \longrightarrow x = - 4$

Verification :-

Putting -4 in place of x →

$\longrightarrow {x}^{2} + 8x + 16 \\ \\ \longrightarrow {( - 4)}^{2} + 8( - 4) + 16 \\ \\\longrightarrow 16 - 32 + 16 \\ \\ \longrightarrow 32 - 32 \\ \\\longrightarrow 0$