Question

x²-8x+6=0 solve using formula
$quadratic equation$
​

Answer 1

ek vargakar mej ka parimap 80 sentimeeter hai mej ka chetraphal kya hoga

Answer 2

The given quadratic equation x²

+8x+6=0 is in the form ax²

+bx+c=0 where a=1,b=8 and c=6.

We know that the quadratic formula is

$x= \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$,Therefore,

substitute a=1,b=8 and c=6 in x=

$\frac{- b± \sqrt{ {b}^{2} −4ac} }{2a}$as follows:

$x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} =$

$\frac{−8± \sqrt{ {8}^{2} - (4 \times 1 \times 6)} }{2 \times 1} = \frac{−8± \sqrt{64 - 24} }{2}$

$= \frac{−8± \sqrt{40} }{2} = \frac{−8± \sqrt{4 \times 10} }{2} =$

$\frac{−8±2 \sqrt{10} }{2} = \frac{2( - 4± \sqrt{10} }{2} = - 4± \sqrt{10}$

Hence,

$x=−4+ \sqrt{10} \: \: or \: \: x=−4− \sqrt{10}$