Question

X2 + 8x - 6, find the zeroes by the middle spilliting term​

Answer 1

Step-by-step explanation:

$\tt We\: have,$

$\tt x^2+8x-6=0$

The first term is, x² its coefficient is 1 .

The middle term is, +8x its coefficient is 8 .

The last term, "the constant", is -6

Step-1 : Multiply the coefficient of the first term by the constant 1 • -6 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is 8 .

-6 + 1 = -5

-3 + 2 = -1

-2 + 3 = 1

-1 + 6 = 5

Observation : No two such factors can be found !!