x²+(9-x)²=41
answer please
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Solution:
Given,
→ x² + (9 - x)² = 41
Using identity - (a - b)² = a² - 2ab + b², expand..
→ x² + x² - 18x + 81 - 41 = 0
→ 2x² - 18x + 40 = 0
→ 2(x² - 9x + 20) = 0
→ x² - 9x + 20 = 0
→ x² - 4x - 5x + 20 = 0
Taking x and -5 as common, we get,
→ x(x - 4) - 5(x - 4) = 0
→ (x - 4)(x - 5) = 0
So,
→ (x - 5) = 0 or (x - 4) = 0
→ x = 4, 5
Answer:
- x = 4, 5
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