Question

x2-9/x+3 =4/7. Find x in this equation and please give me process also.

Answer 1

Given equation : $\dfrac{x^{2}-9}{x+3}=\dfrac{4}{7}$

$\dfrac{x^{2}-3^{2}}{x+3}=\dfrac{4}{7}$

We can factorize x^2 - 3^2 by the identity a^2 - b^2 = ( a + b )( a - b ) where we can assume a as x and b as 3. So, x^2 - 3^2 = ( x + 3 ) ( x - 3 ).

$\dfrac{(x+3)(x-3)}{x+3}=\dfrac{4}{7}$

( x - 3 ) = $\dfrac{4}{7}$

7( x - 3 ) = 4

7x - 21 = 4

7x = 4 + 21

7x = 25

x = 25 / 7

Therefore the value of x satisfying the equation is 25 / 7 .

Answer 2

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