Question

x²/9 + y²/36=1 at(-1,4√2),Find the equation of the tangent to given curves at given point.

Answer 1

check if I have done it correctly....
and do reply...

Answer 2

Answer:

x-y√2+9=0

Step-by-step explanation:

The given curve is x²/9+y²/36=1 ....... (1) and (-1, 4√2) is a given point on this curve.

We have to find the tangent to the curve (1) at that given point.

Now, differentiating the equation (1) with respect to x, we get,

2x/9+y/18(dy/dx)=0, ⇒dy/dx= -4(x/y).

Hence, dy/dx at (-1,4√2) = 1/√2

Therefore, the equation of tangent is (y-4√2)=1/√2(x+1)

⇒y√2-8=x+1

⇒x-y√2 +9=0 . (Answer)