Question

x2-9x+y2+16=0 then find centre and radius of the equation​

Answer 1

Step-by-step explanation:

x^2-2.3x+3^2+y^2+7=0

(x-3)^2+y^2=-7

(x-3)^2+(y-0)^2=-7

centre=(3,0)

radius=sqrt(9+7) (sqrt of g^2+f^2-c)

=sqrt(16)

=4