Question

x2 + (a+1/a) x+1 = 0​

Answer 1

Answer:

x =(a+1) Or x = -(a+2) are two roots of given quadratic equation.

Explanation:

Explanation:

Given quadratic equation :

x²+x-(a+1)(a+2)=0

Splitting the middle term, we get

=> x²-(a+1)x+(a+2)x-(a+1)(a+2)=0

=> x[x-(a+1)]+(a+2)[x-(a+1)]=0

=> [x-(a+1)][x+(a+2)]=0

=> x-(a+1)=0 Or x+(a+2)=0

=> x = (a+1) Or x = -(a+2)

Therefore,

x =(a+1) Or x = -(a+2) are two roots of given quadratic equation.