x² + (a + 1\a)x+ 1 = 0
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Answer:
x² + (a + 1/a)x+ 1
x² + ax + x/a+ 1 = 0
x(x+a)+1/a(x+a) = 0
(x+a)(x+1/a) = 0
Therefore, x=(-a),(-1/a)
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