Question

x2+(a+1)x+b are 2 and -3 then find the value of a+b

Answer 1

Answer:

Step-by-step explanation:

$2 \ and -3 \ are \ zeros \ of \ x^2+(a+1)x+b\\\\\therefore -(a+1) =2-3\\\\-a-1=-1\\\\-a=0\\\\\bf{ a=0}\\\\Also \ \frac b1 =(2)(-3)\\\\\bf b=-6$