Question

x²+(a+3)x-(a+5)=0...?​

Answer 1

Answer:

Let's solve for a.

x2+(a+3)(x)−(a+5)=0

Step 1: Add -x^2 to both sides.

ax+x2−a+3x−5+−x2=0+−x2

ax−a+3x−5=−x2

Step 2: Add -3x to both sides.

ax−a+3x−5+−3x=−x2+−3x

ax−a−5=−x2−3x

Step 3: Add 5 to both sides.

ax−a−5+5=−x2−3x+5

ax−a=−x2−3x+5

Step 4: Factor out variable a.

a(x−1)=−x2−3x+5

Step 5: Divide both sides by x-1.

a(x−1)/x−1=−x2−3x+5/x−1

a=−x2−3x+5/x−1

Answer:

a=−x2−3x+5/x−1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

The minimum possible value of the sum of the squares of the roots of the equation x^2 + (a + 3)x – (a + 5) = 0 is

A) 1

B) 2

C) 3

D) 4