Question

x² + (a+b+c) x+ab+ bc​

Answer 1

Answer:

x2+ax+bx+cx+ab+bx.

x(x+b)+a(x+b)+(x+b)

(x+b)(x+a+c).

Answer 2

Answer:

(x+b)(x+a+c)

Step-by-step explanation:

x² + (a+b+c)x + ab + bc

x² + ax + bx + cx + ab + bc

x² + bx + ax + ab + cx + bc

x(x + b) + a(x + b) + c(x + b)

Taking (x + b) as common,

(x+b)(x+a+c)

Therefore, x² + (a+b+c)x + ab + bc = (x+b)(x+a+c)