Question

x2-(a2+b2) x2+(a2-b2)2=0 imidiatly pls​

Answer 1

Answer:

D=b 2 −4ac=0=2[2(a+b)] 2 −2[2(a 2 +b 2 )][1]=4(a+b) 2 −8(a 2 +b 2 )=4a 2 +4b +8ab−8a2−8b 2=−4a 2 −4b 2 +8ab=−4(a−b) 2

must be less than zero

Hence no real roots.