Question

x2+ax+b=0 then find x

Answer 1

x^2 + ax + b = 0

Discriminant = a^2 - 4(1)(b) = a^2 - 4b

Now,
Zeroes of the given quadratic equation become

x = -a +- √a^2-4b / 2

According to the sridharacharya formula.

Hope this helps you !!

Answer 2

Hey friend, Harish here.

Here is your answer.

Using the quadratic formula gives you the direct solution:

Quadratic formula:

For a general quadratic equation px² + qx + r = 0 , by using quadratic formula we the value of x.

(i.e) $\mathrm{ x=\frac{-q \± \sqrt{q^2 - (4pr)}}{2p} }$

Now, Arriving to the question:

We have ; p = 1 , q = a , r = b

Then,

$\boxed{x =\frac{-a \± \sqrt{a^2 - 4b}}{2} }$

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Hope my answer is helpful to you.