(x2 + bx - 2)(x + 3) = x3 + 6x2 + 7x - 6
Answers
Step-by-step explanation:
(x^2+b*x-2)*(x+3)-(x^3+6*x^2+7*x-6)=0
Step by step solution :
STEP 1 :
Equation at the end of step 1
((((x2)+xb)-2)•(x+3))-((((x3)+(2•3x2))+7x)-6) = 0
STEP 2 :
Trying to factor a multi variable polynomial
2.1 Factoring x2 + xb - 2
Try to factor this multi-variable trinomial using trial and error
Factorization fails
Equation at the end of step 2 :
(x2 + xb - 2) • (x + 3) - (x3 + 6x2 + 7x - 6) = 0
STEP 3 :
STEP 4 : Pulling out like terms
4.1 Pull out like factors :
x2b - 3x2 + 3xb - 9x =
x • (xb - 3x + 3b - 9)
Equation at the end of step 4 :
x • (xb - 3x + 3b - 9) = 0
STEP 5 : Theory - Roots of a product
5.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation:
5.2 Solve : x = 0
Solution is x = 0
Solving a Single Variable Equation:
5.3 Solve xb-3x+3b-9 = 0
In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.
We shall not handle this type of equations at this time.
One solution was found :
x = 0