x² - (K+6)20 - 2(2k +) . find the value of k where the sum of the zero is half of their product
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Let the roots be α,β
Fir a quadratic equation ax²+bx+c=0
Sum of roots α+β=k+6⋯(1)
Product of roots αβ=4k−2⋯(2)
According to question,
α+β= αβ/2
From (1),(2)
⟹k+6=2k−1
⟹k=7
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