Question

x² + kx - 4=0 (real and distinct roots)​

Answer 1

Answer:

${x}^{2} + kn - 4 = 0$

$(x \times x) + kn - 4 = 0$

$2x + kn - 4 = 0$

$2x + kn = 4 - 0$

$2x + kn = 4$

is your right answer

real distinct root =x²

Answer 2

Answer:

The given equation is x

2

+ax−4=0

Comparing given equation with ax

2

+bx+c=0

∴a=1,b=a,c=−4

The discriminant of the given equation is given by D=b

2

−4ac=a

2

−4×−4=a

2

+16

Clearly, D=a

2

+16>0 for all a∈R

Hence, the given equation has real and distinct roots.