Question

x²+kx-4,x=-4 I WILL GIVE MUCH POINT​

Answer 1

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Answer 2

Answer:

Given Quadratic Equation is x^2 - kx + 4 = 0.

Comparing Equation with ax^2 + bx + c =

0

a = 1, b = -k, c = 4.

Given that the Equation has real roots.

D=0

b^2 - 4ac = 0

(-k)^2 - 4(1)(4) = 0

k^2 - 16 = 0

k^2 = 16

k = 4 (or) - 4.

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Step-by-step explanation:

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