Question

X2+kx+(k-1) =0 has both roots positive then find value of k​

Answer 1

${x}^{2} + {k}^{} x \: +$

x²+Kx+k-1= 0

a is equals to 1

b is equals to Kx
and C is equals to K - 1

by adding the discriminant formula

∆=b²-4ac
here b is equals to K X and is equals to 1 and C is equals to K - 1
∆= k²-4×1×k-1

∆ =k²-4×k-1

k²=-4×k-1

Answer 2

Step-by-step explanation:

Hope you understand.

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