x²-(root 2 + 1)x + root 2
markjoseph:
simplify
Answers
Answered by
1
x²-(√2+1)x+√2
√2
^
√2. 1
x²-√2x-1x+√2
taking common
x(x-√2)-1(x-√2)
(x-1) (x-√2)=0
x-1=0 or x-√2=0
x=1 or x=√2
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